am having this vector of value:
[1] 0.9324929 0.9461874 0.9899430 0.8592746 0.9495612 1.0047946 0.9501648 0.8826660 0.9297847
[10] 0.9540155 0.9096408 0.9808021 0.9641611 0.9327183 0.9893001 0.9998917 0.8869922 1.0003532
[19] 0.9934479 0.9547312 0.9376618 0.9911494 0.9544154 0.9626668 0.9733901 0.9406843 0.9781659
[28] 0.9691705 0.9860182 0.9110487 0.9248749 0.9941826 0.9268455 0.9975929 0.9382284 0.9718256
[37] 0.9540453 0.9849839 0.9814700 0.9745441 0.9785246 0.9801577 0.8183103 0.9939775 0.9872761
[46] 1.0038558 0.9343682 0.9491356 0.9022990 0.9682440 0.9772953 0.9686033 1.0102170 0.9819136
[55] 0.9379499 0.9581504 0.9434762 0.9587864 0.8591005 0.9537204 0.8371453 0.9970909 0.9727121
[64] 0.9366303 0.9940191 0.9455938 0.9600928 0.9659665 0.9834040 0.7780706 0.9629880 0.9862824
[73] 0.8911732 0.9908817 0.9618327 0.9399749 0.9856844 1.0088414 0.9585859 0.9633556 0.9364963
[82] 0.9302964 0.9712584 0.9875152 0.8663259 0.9486364 0.9416057 0.9331992 0.9006658 0.9704888
[91] 0.9763257 0.9785422 0.9794852 1.0041416 0.9897161 0.9402995 0.9772260 0.9663181 0.9785556
[100] 0.9025224
know I want to confront it with this value seq(0.76,1.16,0.02) and create frequency table. i did the same thing in excel and this is the result:
Bins Frequency
0,76 0%
0,78 1%
0,80 0%
0,82 1%
0,84 1%
0,86 2%
0,88 1%
0,90 3%
0,92 5%
0,94 14%
0,96 18%
0,98 25%
1,00 23%
1,02 6%
1,04 0%
1,06 0%
1,08 0%
1,10 0%
1,12 0%
1,14 0%
1,16 0%
the function i used in excel is =FREQUENcy(L2:DG2;A2:A22)/Count.Number(L2:DG2). Can someone help me replicate this in R