i have a large dataframe with 1365 columns as shown in the example:
df <- data.frame(X1 = c(7.48, 7.59), Y1 = c(49.16, 48.70), ID1 = c("B_1", "B_1_2"), TI1 = c(191.31, 1349.93),
X2 = c(8.15, 8.06), Y2 = c(48.40, 48.18), ID2 = c("B_1", "B_1_2"), TI2 = c(191.39, 1349.97),
X3 = c(8.80, 8.87), Y3 = c(47.65, 47.20), ID3 = c("B_1", "B_1_2"), TI3 = c(191.48, 1350.05))
now I would like to split this dataframe into a list of dataframes (i.e. three dataframes in this list; 12/4 = 3). the expected list that looks like as follows:
dflist[[1]]
X1 Y1 ID1 TI1
7.48 49.16 B_1 191.31
7.59 48.70 B_1_2 1349.93
dflist[[2]]
X2 Y2 ID2 TI2
8.15 48.40 B_1 191.39
8.06 48.18 B_1_2 1349.97
dflist[[3]]
X3 Y3 ID3 TI3
8.80 47.65 B_1 191.48
8.87 47.20 B_1_2 1350.05
and i would like to rearrange (in ascending order) the data in each dataframe of the list based on column 4 of each dataframe
first to convert the dataframe into list, i used the following code but not working
n <- seq(1,12, by = 4)
my_data <- list()
for (i in 3) {
for (j in seq(1, 12, by = 4)) {
my_data[[i]] <- df3[, j:j+3]
}
}
for sorting the list the following code is used:
dflist1 <- lapply(dflist, function(1){
1[with(dflist, order[, 4]), ]
})
looking for the code to get the expected output (dflist) as presented above